按钮式:
<INPUT name=”pclog” type=”button” value=”GO” onClick=”location.href=’https://www.phpnote.cc/'”>
链接式:
<a href=”javascript:history.go(-1)”>返回上一步</a>
<a href=”<%=Request.ServerVariables(“HTTP_REFERER”)%>”>返回上一步</a>
直接跳转式:
<script>window.location.href=’https://www.phpnote.cc’;</script>
开新窗口:
<a href=”javascript:” onClick=”window.open(‘https://www.phpnote.cc’,”,’height=500,width=611,scrollbars=yes,status=yes’)”>php笔记</a>
=====javascript中弹出选择框跳转到其他页面=====
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<script language="javascript"> <!-- function logout()...{ if (confirm("你确定要注销身份吗?是-选择确定,否-选择取消"))...{ window.location.href="phpnote.cc?login=logout" } } --> </script> |
=====javascript中弹出提示框跳转到其他页面=====
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<script language="javascript"> <!-- function logout()...{ alert("你确定要注销身份吗?"); window.location.href="phpnote.cc?login=logout" } --> </script> |
JavaScript实现页面跳转的五种方式
页面跳转方法一:
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<script type="text/javascript" language="javascript"> window.location.href="blog.php?backurl="+window.location.href; </script> |
页面跳转方法二:
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<script type="text/javascript" language="javascript"> alert("返回"); window.history.back(-1); </script> |
页面跳转方法三:
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<script type="text/javascript" language="javascript"> window.navigate("http://blog.kydbk.com"); </script> |
页面跳转方法四:
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<script type="text/javascript" language="JavaScript"> self.location='top.htm'; </script> |
页面跳转方法五:
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<script type="text/javascript" language="javascript"> alert("非法访问!"); top.location='http://blog.kydbk.com'; </script> |
转载请注明:PHP笔记 » JavaScript实现页面跳转的五种方式